Two ladders are leaning against opposite walls in an alleyway. The bottom of each ladder is placed on the ground in the opposite corner. One ladder is 4m long, the other is 3m long. The height at which the two ladders meet is 1m.

**Question: How far are the walls apart?**

nice one!

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ReplyDelete@Aaron sqrt(143/17)+sqrt(143/10) = 6.68

ReplyDeleteThat would make both ladders fall down. Sorry :(

assuming the walls are perpendicular to the floor

ReplyDeletehttp://www.wolframalpha.com/input/?i=solve+1%3D+1%2Fsqrt%289-d^2%29+%2B+1%2Fsqrt%2816-d^2%29

solve: 1/sqrt(9-d*d) + 1/sqrt(16-d*d) = 1

ReplyDeleteanswer: d = 2.6032877544

2 meters

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